Hello Murray, > Now I'm doing this: > step.leftOuterJoin(tableName + " AS " + aliasName).on(condition);
Yes, that is the simplest way > But I would like to use a Table<Record> instead of that table name > string, via the new Factory.tableByName() method. You can use as() on any org.jooq.Table. Write: tableByName(tableName).as(aliasName)
