To tell you the truth, your code is very complex. There is no clarity in there.
If you want to learn something, learn it simply.
You should define Animal as a separate class with proper method overloading
(same method with different arguments). Put main method into a class of its
own.
I also don't see the purpose of sending arguments like "Cat c" or "Dog d" when
you aren't even using it.
What do you expect an.child(null) to print??? Of course, it might only print
"Animal" (I think it shouldn't print anything).
Your method declaration--> void child(Animal a){System.out.println("
Animal");} should be rewritten as [ void child(){System.out.println("Animal");}
and your function call an.child(null) should be [an.child()]
Advice:
Rewrite your program with more clarity and simplicity and then tell if you face
same problem.
--- On Wed, 2/15/12, ABHISHEK TRIPATHI <[email protected]> wrote:
From: ABHISHEK TRIPATHI <[email protected]>
Subject: [jpassion_java] Overloaded method
To: "JPassion.com: Java Programming" <[email protected]>
Date: Wednesday, February 15, 2012, 11:04 PM
Hi,
Can you plz tell why output is coming as Cat not Animal?
Also if I un-comment all lines, I get compile time error.
thanks
Abhi
***********************************
package Overload;
public class Animal {
// void child(Dog d) {System.out.println(" Dog");}
void child(Cat c){System.out.println(" Cat");}
void child(Animal a){System.out.println(" Animal");}
// void child(Mouse m){System.out.println(" Mouse");}
// private void child(Cat x){}
public static void main(String[] args) {
Animal an=new Animal();
an.child(null);
}
}
************
class Dog extends Animal{}
class Cat extends Animal{}
class Mouse extends Dog{}
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