Hi Sunil
Please try this:
/**
* @author mihai 2012-02-28
*/
public class TestMultiArray {
public static void main(String[] args) {
// Array of arrays of int, instantiated as a 3 element array
// (each element is an array of int)
int[][] myArray = new int[3][];
for (int i = 0 ; i < myArray.length ; i++ ){
// Instantiate each element of the Array with an array of int
// of random size (I don't know how many ints are in
the array)
myArray[i] = new int[(int)Math.round(1 + 10 *
Math.random())];
// For each element of the array (which is an element of the Array)
for (int j = 0 ; j < myArray[i].length ; j++){
// ... assign a value in sequence
myArray[i][j] = j;
}
}
// Now print all the elements of the Array:
for (int[] a : myArray){// For each element a of the Array
(an array)
for (int n : a){// for each element n of the array
System.out.print("\t" + n);// Print tab-separated
values
}
// Pass to the next line
System.out.println();
}
}
}
The printed result may vary from one execution to another (due to the
"random"), for e.g.:
* 0 1
0 1 2 3 4 5 6 7 8 9
0 1 2 3 4 5*
Hope it helps
Mihai
On 28/02/2012 04:51, sunil atluri wrote:
I understand that you can use<array name>.length property toknow the
length and loop through to get values for specific element of a single
dimensional array.
Is it possible to do the same (instead of harcoding) for a
multidimensional array? If so, can you show me an example?
Thanks
Sunil Atluri
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