that's really neat, thank you.
On Sep 12, 4:35 am, "Jörn Zaefferer" <[EMAIL PROTECTED]>
wrote:
> A bit simpler:
>
> $.fn.relation = function(handler) {
> $.each(this[0], handler);
>
> });
>
> Jörn
>
> On Thu, Sep 11, 2008 at 5:24 PM, Galen <[EMAIL PROTECTED]> wrote:
>
> > thx.
> > But I've come up with a new wrapper set method to accomplish the goal.
>
> > $.fn.relation=function(handler) {
> > $.each(this[0], function(key,val) {
> > handler(key,val);
> > });
> > };
> > $({a:1,b:2}).relation(function(n1,n2) {
> > alert(n1+": "+n2);
> > });
>
> > On Sep 11, 4:55 am, Ariel Flesler <[EMAIL PROTECTED]> wrote:
> >> Or use DOM traversal (f.e using css classes).
>
> >> --
> >> Ariel Fleslerhttp://flesler.blogspot.com/
>
> >> On Sep 10, 8:57 am, Galen <[EMAIL PROTECTED]> wrote:
>
> >> > Sometimes we need to build relaitons between two sets of elements. For
> >> > example, a bunch of buttons will cause a bunch of menus to slide. In
> >> > such case, we will have to register event listener for each of them.
> >> > what if we can write the code like this:
>
> >> > $({
> >> > "#button1": "#menu1",
> >> > "#button2": "#menu2,#menu3"
> >> > "#button3, #button4": "#menu4,#menu5"}.click(function(slave) {
>
> >> > var button=this;
> >> > var menu=slave;
> >> > button.toggleClass("clicked");
> >> > menu.slideToggle("slow");
>
> >> > });
>
> >> > with the single statement executed, we have the relations between the
> >> > buttons and the menus as follow:
>
> >> > button1 will cause menu1 to slide.
> >> > button2 will cause menu2 and menu3 to slide at the same time.
> >> > both buttton3 and button4 will cause menu4 and menu5 to slide at the
> >> > same time.
>
> >> > There may be some potential problems, though.
> >> > i don't know how to call the returned wrapped set, and i'll call it
> >> > the "relative wrapped set" for the moment. Hope u don't mind.
> >> > So, do u think it is possible to write code like this?
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