i came up with another idea:

            // Everything in a should be in b and equivalent and ...
            for (var i in a) {
                    if (!(a.hasOwnProperty(i) && b.hasOwnProperty(i) &&
equiv(a[i], b[i]))) {
                            return false;
                    }
            }

            // is there any property in b left, which doesn't exist in
a?
            for (var i in b) {
                if (b.hasOwnProperty(i) && !a.hasOwnProperty(i)) {
                    return false;
                }
            }

maybe you can give it a try and also perform a benchmark (maybe you
could share your test and benchmark, so I can also test my ideas on my
machine...)

bye, markus

On 22 Okt., 11:14, "markus.staab" <[EMAIL PROTECTED]> wrote:
> hi Philippe,
>
> in your new code you are doing the following:
>
> 50                  // Stack all property names for a last minute check for
> two good reasons:
> 51                  // 1) To prevent failing when comparing
> 52                  //      a property that have an undefined value
> 53                  //      with a property that do not exists.
> 54                  // 2) To allow verifying equivalence in one way (a ->
> b)
> 55                  //      and then comparing both property names to
> replace
> 56                  //      (b -> a) processing. It's faster.
> 57                  var aProperties = [], bProperties = [];
> 58
> 59                  // Verify a's properties with b's properties
> 60                  for (i in a) {
> 61                      if (eq) {
> 62                          if (a.hasOwnProperty(i)) {
> 63                              aProperties.push(i);
> 64                              eq = equiv(a[i], b[i]);
> 65                          }
> 66                      } else {
> 67                          return false;
> 68                      }
> 69                  }
> 70
> 71                  // Get only b's property names
> 72                  if (eq) {
> 73                      for (i in b) {
> 74                          if (b.hasOwnProperty(i)) {
> 75                              bProperties.push(i);
> 76                          }
> 77                      }
> 78                  }
> 79
> 80                  // Finally, ensures also the same property names in
> both ways.
> 81                  // That will also ensures that no property with
> undefined value is left behind.
> 82                  return eq && equiv(aProperties, bProperties);
>
> in this you compare the properties from a and b twice. line 64 should
> be deleted. the properties are compared in the next recursion anyway.
> make the 2 "for (x in y)"-loops less complex and only collect the
> properties. but then it would be optimized for the "eqiv"-case.
>
> On 21 Okt., 22:55, Philippe Rathe <[EMAIL PROTECTED]> wrote:
>
> > Please don't use that patch because it breaks the QUnit equiv test  
> > suites.
> > My explanations can be found in my previous post.
>
> > For some of the patched code that can be use, some benchmark need to  
> > be done anyway.
>
> > Thanks anyway.
>
> > Philippe Rathé
> > On 21-Oct-08, at 2:42 PM, markus.staab wrote:
>
> > > Index: testrunner.js
> > > ===================================================================
> > > --- testrunner.js  (revision 5901)
> > > +++ testrunner.js  (working copy)
> > > @@ -428,8 +428,8 @@
> > >             if (len !== b.length) { // safe and faster
> > >                 return false;
> > >             }
> > > -            for (var i = 0; i < len; i++) {
> > > -                eq = eq && equiv(a[i], b[i]);
> > > +            for (var i = 0; i < len && eq; i++) {
> > > +                eq = equiv(a[i], b[i]);
> > >             }
> > >             return eq;
> > >         }
> > > @@ -447,15 +447,15 @@
>
> > >             // Everything in a should be in b and equivalent and ...
> > >             for (var i in a) {
> > > -                if (a.hasOwnProperty(i)) {
> > > -                    eq = eq && equiv(a[i], b[i]);
> > > +                if (!a.hasOwnProperty(i) || !equiv(a[i], b[i])) {
> > > +                    return false;
> > >                 }
> > >             }
>
> > >             // ... everything in b should be in a and equivalent
> > >             for (var i in b) {
> > > -                if (b.hasOwnProperty(i)) {
> > > -                    eq = eq && equiv(b[i], a[i]);
> > > +                if (!b.hasOwnProperty(i) || !equiv(b[i], a[i])) {
> > > +                    return false;
> > >                 }
> > >             }
>
> > > On 21 Okt., 19:47, "Jörn Zaefferer" <[EMAIL PROTECTED]>
> > > wrote:
> > >> Could you provide these as patches against the current 
> > >> revision?http://jqueryjs.googlecode.com/svn/trunk/qunit/testrunner.js
>
> > >> Thanks
> > >> Jörn
>
> > >> On Tue, Oct 21, 2008 at 7:35 PM, markus.staab  
> > >> <[EMAIL PROTECTED]> wrote:
>
> > >>> even shorter
>
> > >>> 52                  for (var i in a) {
> > >>> 53                      if (!a.hasOwnProperty(i) || !equiv(a[i],
> > >>> b[i])) {
> > >>> 54                        return false;
> > >>> 55                      }
> > >>> 56                  }
>
> > >>> On 21 Okt., 19:07, "markus.staab" <[EMAIL PROTECTED]> wrote:
> > >>>> taking a second look at the for (x in y) loops, we could also do  
> > >>>> some
> > >>>> further optimization:
>
> > >>>> 52                  for (var i in a) {
> > >>>> 53                      if (a.hasOwnProperty(i)) {
> > >>>> 54                          if(!equiv(a[i], b[i]))
> > >>>>                                return false;
> > >>>> 55                      } else {
> > >>>>                             return false;
> > >>>>                          }
> > >>>> 56                  }
>
> > >>>> markus.staab schrieb:
>
> > >>>>> in reply to the article athttp://philrathe.com/articles/equiv:
>
> > >>>>> in the equiv method there is several times a loop like
>
> > >>>>> 34             for (var i = 0; i < len; i++) {
> > >>>>> 35                 eq = eq && equiv(a[i], b[i]);
> > >>>>> 36             }
> > >>>>> 37             return eq;
>
> > >>>>> this could be optimized, because if one of the elements is not  
> > >>>>> equal,
> > >>>>> you found, that the origin elements aren't equal..
>
> > >>>>> so better use
>
> > >>>>> 34             for (var i = 0; i < len && eq; i++) {
> > >>>>> 35                 eq = eq && equiv(a[i], b[i]);
> > >>>>> 36             }
> > >>>>> 37             return eq;
>
> > >>>>> see the additional abort condition in the for loop...
> > >>>>> This little "trick" could be applied in several places of the
> > >>>>> function, e.g.
>
> > >>>>> 52             for (var i in a) {
> > >>>>> 53                 if (a.hasOwnProperty(i)) {
> > >>>>> 54                     eq = eq && equiv(a[i], b[i]);
> > >>>>> 55                 }
> > >>>>> 56             }
>
> > >>>>> 59             for (var i in b) {
> > >>>>> 60                 if (b.hasOwnProperty(i)) {
> > >>>>> 61                     eq = eq && equiv(b[i], a[i]);
> > >>>>> 62                 }
> > >>>>> 63             }
>
> > >>>>> in the for(x in y) there should be a break, since there is no  
> > >>>>> abort
> > >>>>> condition.
>
> > >>>>> greets, markus
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