> jQuery([undefined])[0] === jQuery([])[0]
Yes, but
jQuery([undefined]).length !== jQuery([]).length
> eq() always returns a single element, so you'd only need to allow null/
> NaN/""/etc to pass through, I guess:
In the current implementation, eq(i) returns the value (not only
nodes) at index i, if i is not out of range.
In case of "out of range" it returns an "empty" jquery.
> eq: function( i ) {
> var el = [ this[ i<0 ? i+this.length : i] ];
> if (el === undefined) el = [];
> return this.pushStack( el, 'eq', i )
>
> }
Your solution will return "jQuery([undefined])" in case of "out of
range" insted of an "jQuery([])",
and el will always be an array, so (el === undefined) will never be
true.
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