> Well, you do have "babe" appended to your pseudo, so you should
> already be in good shape. ;-)
Yes, I know... I'm really wondering if I shouldn't get rid of this
three year old pseudo and build myself a new identity.
It's actually my family name, babé. As long I was surfing on the
"french" Web it was ok.
Anyway, I was just joking.
On Aug 27, 1:24 pm, Karl Swedberg <k...@englishrules.com> wrote:
> Well, you do have "babe" appended to your pseudo, so you should
> already be in good shape. ;-)
>
> for the record, my reply to holicGirl was purely due to the timing of
> it. For the first time in a long time I had a few minutes to reply on
> this and the jquery-en list (and I didn't see your reply before I
> posted mine).
>
> cheers!
>
> --Karl
>
> ____________
> Karl Swedbergwww.englishrules.comwww.learningjquery.com
>
> On Aug 27, 2009, at 4:00 AM, lrbabe wrote:
>
>
>
> > Next time I register on a Group I'm going to append Girl to my pseudo
> > as well.
> > Look, two detailed answers for one off topic question :D
>
> > On Aug 27, 1:49 am, Karl Swedberg <k...@englishrules.com> wrote:
> >> Hi,
>
> >> if you can use jq('a...@id="myLink"]') then certainly you can use
> >> jq('a#myLink')
>
> >> But to answer your question about the syntax error, it's because the
> >> XPath syntax you're using for the attribute selector was deprecated a
> >> long time ago and finally removed from jQuery in version 1.3. Use the
> >> CSS syntax instead:
> >> jq('a[id=myLink]')
>
> >> In other words, remove the "@". Also, the quotes around myLink are
> >> optional, so I removed them.
> >> Again, though, you'll be in better shape if you use jq('a#myLink'),
> >> or
> >> better yet, jq('#myLink')
>
> >> --Karl
>
> >> ____________
> >> Karl Swedbergwww.englishrules.comwww.learningjquery.com
>
> >> On Aug 26, 2009, at 11:23 AM, holicGirl wrote:
>
> >>> Hello,
> >>> I have a basic knowlegde of jQuery and a problem in selecting a
> >>> link.
> >>> To be specific I've a problem with the syntax.
>
> >>> I'm using several libraries so I can't use for example the $
> >>> ('a#myLink') function but I've to write jq('a...@id="myLink"]').
>
> >>> The application don't recognize the syntax, it shows this message:
> >>> Syntax error, unrecognized expression: [...@id="myLink"]
>
> >>> Can someone help me?
>
> >>> Thanks in advance
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