> I think that would be quite different from the way map currently
> works, which does not modify the array passed in but returns a new
> array whose values are the results of applying the callback function
> to each successive value of the original one.
Maybe jQuery could first clone the object:
var newObj = $.extend( {}, obj );
( It's just for the purpose of demonstration, it might have an issue
of efficiency )
> I'm not making much sense out of that. Are you assuming that every
> property of the "obj" parameter is a function? Can you give some
> context and a more real-world example? This does not sound hard to
> write, but I'm not seeing the benefits.
One scenario is that it will be useful, if we want to modify options a
user passed in, which is normally an object and have callbacks in it.
> I don't know what scoping issue you're talking about, but I think that
> the only real way to enumerate the properties of an object involves
> for-in.
This is what I meant:
Let's say this is the options a user passed in:
var options = {
key: 'value',
callback1: function() {}
callback2: function() {}
}
And we want to modify the callback:
( This snippet won't work )
for( key in options ) {
var option = options[ key ]
if( $.isFunction( option ) )
options[ key ] = function() {
// Call old callback
option();
// Do something else
}
}
It won't work because the "option" here is not scoped, so all modified
callbacks will call whatever callback that is the last one being
iterated.
And it should be written like this:
for( key in options ) {
// Scope them
(function() {
var option = options[ key ]
if( $.isFunction( option ) )
options[ key ] = function() {
// Call old callback
option();
// Do something else
}
})();
}
If $.map() is able to iterate over objects, it won't have the issue of
scoping:
$.map( options, function( option ) {
// No need to scope, because it already does
if( $.isFunction( option ) )
return function() {
// Call old callback
option();
// Do something else
}
})
I feel it's a lot neater.
--
You received this message because you are subscribed to the Google Groups
"jQuery Development" group.
To post to this group, send email to jquery-...@googlegroups.com.
To unsubscribe from this group, send email to
jquery-dev+unsubscr...@googlegroups.com.
For more options, visit this group at
http://groups.google.com/group/jquery-dev?hl=en.
