I'd love to help, but I have absolutely no idea what you're trying to
do! I'd recommend starting with working code, then figure out how to
organize and generalize it.
- Ben
On Nov 25, 4:04 am, Lukáš <lukash...@gmail.com> wrote:
> Hey,
>
> so after some time I decided to look into plugin creation. Since for
> some time I was forced to load up to 30 different variables from
> inputs, so I created a function that would read all the data from one
> instead of multiple inputs. So now I tried to reform it into a plugin.
> The problem starts here.
>
> Here is the code (simplified).
>
> (function($) {
> $.datareader = function(settings) {
> if(!settings) {
> this.settings = $.extend({}, $.datareader.defaults,
> settings);
> } else this.settings = settings;
> };
>
> $.datareader.defaults = {
> bracket: '{}'
> }
>
> $.extend($.fn.dr, {
> update:
> function(input) {
> process(this, false, 'update', input);
> },
> del:
> function(input) {
>
> },
> add:
> function(input) {
>
> }
> });
>
> $.fn.dr = function(settings) {
> this.each(function(settings) {
> process(this, settings);
> });
>
> return this;
> }
>
> })(jQuery);
>
> "process" function in does all the stuff needed since I need it
> multiple times and returns an object. Now my question is about
> "$.fn.dr". How can I force it to return a value instead of just
> executing the function, I tried multiple ways but none of them worked.
> Which would be fine for the functions that extend this one, since
> there I need it to be executed instead of returing a value. Also I
> dont really need the "$.fn.dr" function to loop trough all elements
> since its only for my internal use, I know it will be fired only on
> one.
>
> So to put it simple how can I force the function to return an actual
> value? :)
>
> Oh and one more think. I create a "new $.datareader" object each time
> its fired. Wouldnt that be a major slowdown or something if it will be
> exucuted lets say 20 times? (which can easily happen)
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