I was using the nightly here's some HTML u can copy and paste to reproduce
<script src='http://code.jquery.com/nightlies/jquery-nightly.js'></ script> <div id=x></div> <p>This should log: 1,1,undefined, 40</p> <div id=output></div> <script> $().ready(function(){ console.log($("#x").attr("size")) $("#x").attr("size", 40) console.log($("#x").attr("size")) console.log($("#x").attr("zize")) $("#x").attr("zize", 40) console.log($("#x").attr("zize")) }) </script> On 21 Dec, 16:45, John Resig <jere...@gmail.com> wrote: > What version of jQuery 1.4? This sounds like an issue that was fixed in 1.4a2. > > --John > > > > On Mon, Dec 21, 2009 at 5:29 AM, weepy <jonah...@gmail.com> wrote: > > Worked with 1.3.2 > > > now .attr("size") returns 1 whether it's been set or not > > > $("x").attr("size") => 1 > > > $("x").attr("size", 40) > > > $("x").attr("size") => 1 > > > and no attribute seems to appear on the element. > > > -- > > > You received this message because you are subscribed to the Google Groups > > "jQuery Development" group. > > To post to this group, send email to jquery-...@googlegroups.com. > > To unsubscribe from this group, send email to > > jquery-dev+unsubscr...@googlegroups.com. > > For more options, visit this group > > athttp://groups.google.com/group/jquery-dev?hl=en. -- You received this message because you are subscribed to the Google Groups "jQuery Development" group. To post to this group, send email to jquery-...@googlegroups.com. To unsubscribe from this group, send email to jquery-dev+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/jquery-dev?hl=en.
