Well, I've got your point, and changed my code to var data =
jQuery.extend(true, [], arrComp);
With that, I wanted to make a copy of "arrComp" into "data", so that
deleting something in data won's mess with arrComp, right?
Testing like you did (and even if I make arrComp.toSource() , copy the
content and paste directly in my code, like:)
var arrComp = [{name:'One', value:1}, {name:'Two', value:2}];
var data = jQuery.extend(true, [], arrComp);
It works! Deleting something in data won't change arrComp. But in my
real case, it doesn't work! When I delete something in the data, it
deletes from arrComp as well. I don't know how could I show you this,
I've been trying to reproduce this in small scale, but I had no
success.
If it happens to me to find out a better simulation, I will post here
again. Thanks for you help, though!
On Jan 14, 2:44 am, Dave Methvin <dave.meth...@gmail.com> wrote:
> > x[1] = {twist: 3};
> > alert( x.toSource() ); // [{test:1}, {twist:3}]
>
> My test case was broken! When I change it to this:
>
> var x = [ {test:1}, {toast:2} ];
> var y = $.extend(true, [], x);
> x[1].toast = 3;
> alert( y.toSource() );
>
> I get the expected output:
>
> [{test:1}, {toast:2}]
>
> That is, x was deep-extended to y and a change to x didn't affect y.
>
> So it seems like that should work. Can you show more of the code?
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