[jQuery] Re: $(document).ready( ) ... tricky ajax problem

[Scott Sauyet]

sam wrote:
How do I then run the $(document).ready() function on *only* this new
div that has been inserted into the DOM?  If I rerun the entire $
(document).ready() function, the original "alerter"s will have the
click function bound twice.


There is a optional context to the "$()" method; supply your new div here:

    $(".alerter", $("#newDiv")).click( function(){
        alert('you clicked me.');
    });

You may need to call this in your ajax callback function in order to 
time it properly.

Cheers,

  -- Scott