Hi rob
It seems to me that children() does not accept a params separated with a
comma
would that make sense ?
On 5/31/07, Rob Desbois <[EMAIL PROTECTED]> wrote:
Olivier,
The .siblings() function excludes the elements selected, e.g.:
$("#myId").siblings();
will select all siblings of the element with ID "myId", and will exclude
that element from the results.
--rob
On 5/30/07, Olivier Percebois-Garve <[EMAIL PROTECTED]> wrote:
>
> Thanks a lot.I'll test that tomorrow back at work.It looks correct.
> I never used children(), and its seems to solve issues I had on other
> scripts.
>
> I also dream on a brothers() method (all other siblings except itself)
> ...
>
> Olivier
>
> Rob Desbois wrote:
>
> Yes you're absolutely correct.
>
> Try this:
>
> > jQuery.fn.accordionQuizz = function(accordion) {
> > this.children('[EMAIL PROTECTED], label').each(function(){
> >
>
> I haven't tested it though.
> --rob
>
>
> On 5/30/07, Olivier Percebois-Garve < [EMAIL PROTECTED]> wrote:
> >
> > I dont get it working properly. I tried:
> >
> > $('#accordion').accordionQuizz();
> >
> > jQuery.fn.accordionQuizz = function(accordion){
> > jQuery(this+' [EMAIL PROTECTED], '+this+'
> > label').each(function(){
> >
> >
> >
> > I guess that here <this> is returning the object, wheras I need the
> > selector name.
> > the plugin should apply to to radio inputs and their labels within an
> > element such as #accordion.
> >
> > Olivier
> >
> >
> > On 5/30/07, Rob Desbois < [EMAIL PROTECTED]> wrote:
> > >
> > > Olivier,
> > >
> > > If you call $(...).accordionQuizz() then the jQuery object (result
> > > of $(...)) is accessible via the 'this' object in your function:
> > >
> > > jQuery.fn.accordionQuizz = function(accordion) {
> > > >
> > > alert(this.length); // use the jQuery object
> > > >
> > >
> > > If you call that with:
> > >
> > > > $('#accordion').accordionQuizz();
> > >
> > > then in your accordionQuizz() function, 'this' is the same as
> > > $("#accordion")
> > >
> > > --rob
> > >
> > >
> > > On 5/30/07, Olivier Percebois-Garve < [EMAIL PROTECTED]> wrote:
> > >
> > > > Hi
> > > >
> > > > I am calling my plugin this way :
> > > >
> > > > $().accordionQuizz('accordion');
> > > >
> > > > my plugin gets the param this way :
> > > >
> > > > jQuery.fn.accordionQuizz = function(accordion){
> > > > jQuery(accordion+' [EMAIL PROTECTED], #'+accordion+'
> > > > label').each(function(){
> > > >
> > > >
> > > > How to do in order to call the plugin this way :
> > > >
> > > > $('#accordion').accordionQuizz();
> > > >
> > > >
> > > >
> > > > thanks
> > > >
> > > >
> > > > Olivier
> > > >
> > >
> > >
> > >
> > > --
> > > Rob Desbois
> > > Eml: [EMAIL PROTECTED]
> > > Tel: 01452 760631
> > > Mob: 07946 705987
> > > "There's a whale there's a whale there's a whale fish" he cried, and
> > > the whale was in full view.
> > > ...Then ooh welcome. Ahhh. Ooh mug welcome.
> >
> >
> >
>
>
> --
> Rob Desbois
> Eml: [EMAIL PROTECTED]
> Tel: 01452 760631
> Mob: 07946 705987
> "There's a whale there's a whale there's a whale fish" he cried, and the
> whale was in full view.
> ...Then ooh welcome. Ahhh. Ooh mug welcome.
>
>
>
--
Rob Desbois
Eml: [EMAIL PROTECTED]
Tel: 01452 760631
Mob: 07946 705987
"There's a whale there's a whale there's a whale fish" he cried, and the
whale was in full view.
...Then ooh welcome. Ahhh. Ooh mug welcome.
