$j('<div class="prueba"/>) // this creates the div element
.ventana() // this gets the jQuery object of the just-created div
On Nov 28, 9:38 am, "[EMAIL PROTECTED]"
<[EMAIL PROTECTED]> wrote:
> Hello!
>
> I'm trying to do a window plugin with jQuery, but I have a serious
> problem. My code is based on the UI jQuery Dialog, but I need to
> imlement the windows with canvas and a lot of functions.
>
> I call my function: $j('<iframe src="http://www.google.es/').ventana(), for
> example.
>
> (function($j){
> $j.fn.ventana = function(opciones){
> var o = $j.extend({}, $j.fn.ventana.defaults, opciones);
>
> return this.each(function(){
> if (!($j(this).parent(".ventana").length ||
> $j(el).is(".ventana"))){
> $j.fn.ventana.crearEstructura(this,o);
> }
> $j.fn.ventana.abrirVentana(this);
> });
> };
>
> $j.fn.ventana.crearEstructura = function(contenido,o){
> if ($j(contenido).parent().length){
> contenido = $j(contenido).html();
> contenido.remove();
> }else{
> contenido = $j(contenido).wrap('<div class="auxiliar"></
> div>').html();
> }
>
> And all go well. BUT! When I call my function $j('<div
> class="prueba"/>).ventana(), and that div isn't in the DOM, when I question
> in my
>
> code:
>
> ¿$j(contenido).parent().length?
>
> jQuery say YES!!! Why??? I use Firebug and when I put on the console
> $j(contenido).parent() returns [div]. ¿div? There isn't any div,
> what's happening? Help please!
