pushStack() should return its argument as a jQuery object. So if you
give it an array of elements it should come back as a jQuery
'collection' of those elements.
$([]) gives an empty jQuery object.
On Dec 12, 7:49 pm, McLars <[EMAIL PROTECTED]> wrote:
> I could not get the first example to work. Again, I just can't seem to
> grasp what map does or how to make it work.
>
> The second example is very close to working, except that it returns an
> array, not a jQuery collection. So, let me try rephasing my question.
> How do I create an empty jQuery collection?
>
> I have actually acomplished this, but it's very ugly. Instead of the
> following:
>
> var returnObject = []; //creates an empty array
>
> I used the following:
>
> var returnObject = $(this).not(this);
>
> That seems pretty stupid to me, but it's the only way I could figure
> out to create an empty jQuery collection, to which I can add
> individual jQuery objects from inside my loop. Surely, there is a more
> elegant way to create an empty jQuery collection.
>
> The pushStack suggestion is great, btw.
>
> Thanks again,
>
> Larry
>
> On Dec 12, 4:42 am, Wizzud <[EMAIL PROTECTED]> wrote:
>
> > Simply return your new collection. How you get your new collection
> > from the current object may well involve map(), but however you do it,
> > all you need to do is return whatever collection you want to continue
> > the chain with. It is probably advisable to use pushStack(), so that
> > your original collection can be retrieved further along the 'chain' if
> > desired (by using end()).
>
> > eg.
>
> > $.fn.myMethod = function() {
> > return this.pushStack( this.map(function(i,elem) {
> > //
> > // return newElement
> > //
> > }) );
>
> > };
>
> > or
>
> > $.fn.myMethod = function() {
> > var returnObject = [];
> > this.each(function() {
> > // var newElement = something based on 'this'
> > // returnObject.push(newElement);
> > });
> > return this.pushStack(returnObject);
>
> > };
>
> > or variations thereof.
>
> > On Dec 12, 3:01 am, McLars <[EMAIL PROTECTED]> wrote:
>
> > > I have a plugin that needs to return a different jQuery collection
> > > than the one it was passed. In other words, each of the elements
> > > passed in the original collection will create a new element, and I
> > > want to return the new elements instead of the originals.
>
> > > So, instead of something like this:
>
> > > $.fn.myMethod = function() {
> > > return this.each(function() {
> > > //
> > > // Create new element here
> > > //
>
> > > });
>
> > > which returns the original element collection (preserves chaining),
> > > I'm looking for an elegant way to return the new elements in a jQuery
> > > collection.
>
> > > I think maybe the $.map method might be part of the solution, but I'm
> > > afraid I just can't understand how. Any help would be appreciated.
>
> > > Thanks,
>
> > > Larry- Hide quoted text -
>
> > - Show quoted text -
