[jQuery] Re: Is it possible get the data from ajaxSuccess?

[Mario Moura]

  Wow, thanks a lot Richard

I can do this with php (quite simple) but I am lost with Jquery / Javascript
syntax. Could you help me?

Example

     $("#mychild").ajaxForm({
        success:
            function(data) {
                  // do stuff with data;
                function toCheck() {
                    $(data);
                }
            }
        });

        // So for each Ajax request I will insert
            function toCheck() {
                $(data);  // or I can get some data into $data like
$(data).attr("myid")
            }

        // So I want check if toCheck() have a value or not but I will let
simple, just alert me.
        // I dont know if the syntax is ok

            function pleaseAlertMe() {
                alert(toCheck());
            }

            I dont want (or I cant) pass the $(data) to a div and check
there by DOM I prefer check by function. If is it possible of course.

            And now I will study a lot of JavaScript Syntax. ;)

Regards

Mario Moura

2007/12/14, Richard D. Worth <[EMAIL PROTECTED]>:
>
> You could declare a function and give it a name, instead of using an
> anonymous function, then pass that as the success function for each ajax
> call.
>
> - Richard
>
> On Dec 14, 2007 8:51 AM, Mario Moura < [EMAIL PROTECTED]> wrote:
>
> > No.
> >
> > Let me explain better.
> >
> > In your scenario you made a individual AJAX request and into this
> > request you create rules.
> >
> > But JQuery  could create an universal AjaxSucess to test all data from
> > all ajax requests.
> >
> > So imagine this scenario:
> >
> > The page have a lot of AJAX requests, something like ajaxform, $.ajax,
> > $.post, $.get
> >
> > So from response of each AJAX we could create a function like: (and I
> > will use switch)
> >
> >
> > $().ajaxSuccess (function() {
> >          switch( $(data).attr("id")  ) { // here I get the data from
> > AJAX Sucess every time happen could by by xml, json but I am using div
> >             case 'myid':
> >                 // do stuff with data;
> >             break;
> >             case 'myid2':
> >                // do stuff with data;
> >             break;
> >          }
> >
> > no matter if it is from $.ajax({"type": "POST",  "url": " foo1.php ",});
> > or  $.ajax({"type": "POST", "url": "foo2.php "}); or $.ajax({"type":
> > "POST", "url": "foo3.php ",});
> >
> > But at this moment. I think is not possible. But could be a good
> > improve.
> >
> > Did you understand?
> >
> > Regards
> >
> > Mario Moura
> >
> > 2007/12/14, Giovanni Battista Lenoci <[EMAIL PROTECTED]>:
> >
> > >
> > > Don't know if I understood,
> > >
> > >    $.ajax({"type": "POST",
> > >       "url": " foo2.php",
> > >       "data": data,
> > >       "dataType": "json",
> > >       "success": function(server_response) {
> > >           switch(server_response.wich_function) {
> > >              case '1':
> > >                 on_success_one(server_response);
> > >              break;
> > >              case '2':
> > >                 on_success_two(server_response);
> > >              break;
> > >           }
> > >
> > >       });
> > >
> > >
> >
> >
> > --
> > Mário Alberto Chaves Moura
> > [EMAIL PROTECTED]
> > 31-3264-6203
> > 31-9157-6000
>
>
>


-- 
Mário Alberto Chaves Moura
[EMAIL PROTECTED]
31-3264-6203
31-9157-6000