JJShell:
You can address both issues by using all inputs within a form
var values = {};
$("form").find("input:text").each(function(){
values[$(this).attr("name")] = $(this).val();
});
Now values will have the following structure for your second example, which
PHP should automatically turn into an array within $_POST:
{
"pagetitle[1]" : "test",
"pagetitle[2]" : "some title",
"pagetitle[3]" : "some other title"
}
- jake
On Dec 21, 2007 3:00 AM, jjshell <[EMAIL PROTECTED]> wrote:
>
> First of all, thanks for your time and answers. I really appreciate
> it. Having made a few tests, the $.ajax approach seems the one that
> fits the most my application.
>
> Just a few questions:
>
> 1.
> Can you avoid to explicitely name each field of your form?
> data: "test=" + $("input[name=test]").val(),
> What if a form is dynamically created server-side? Do you also have to
> dynamically create a line for jQuery?
>
> 2.
> How dows this approach reacts to array fields?
>
> <input type="text" name="pagetitle[1]" value="test" />
> <input type="text" name="pagetitle[2]" value="some title" />
> <input type="text" name="pagetitle[3]" value="some other title" />
>
> Thank you again for your time :)
>
