One way to solve your dilemma is to use tr:nth-child(even). That will
select all table rows that are an "even" child of their parent
element. This should work:
$("table tr:nth-child(even)").css("background", "#cccccc");
--Karl
_________________
Karl Swedberg
www.englishrules.com
www.learningjquery.com
On Feb 4, 2008, at 5:38 PM, Snef wrote:
Hi,
I know how to do some 'zebra-striping' on tables with jQ, but i have a
little problem.
I have some (unknown amount) tables om a page and I want to 'stripe'
the tables seperately, so that all striping is the same in each table.
With a simple:
$("table tr:even").css("background", "#cccccc") the rows are counted
over all the tables and I want to start counting (for even and odd
rows) for every table, so i tought:
$("table").each(function() {
// how to get the rows here???
})
How do I do this? (I do not know on forehand how many or which tables
are on the page....)
