I tried what you said but it does not work... now both links go to the same
page when clicked...
RotinPain wrote:
>
>
> the problem is quite simple i think, all your links have the same id
> (generate2)
> And the jquery function is attached to a link with this id (generate2)
> So only 1 link will be responding to the function.
>
> You need to use each() to attach an event to each links. Like
>
> $("#generate2").each (
> function () {
> $( this ).bind (
> "click",
> function(){
> //dosomething your stuff here
> }//function
> );//bind
> }//function
> );//each
>
> This should normally work. But note that only one unique ID per page
> is acceptable (see W3C recommandations). Better to use class name
> filtering instead (there could be more than 1 time the same class on
> the page but only 1 unique id).
> It will only change the first line:
> $(".generate2").each ( ...
>
> And the HTML will looks like
> # ...
>
> On Oct 21, 3:56 pm, Flavio333 <[EMAIL PROTECTED]> wrote:
>> Hello, I an quite new to jquery and hope someone can help with my
>> problem. I
>> am trying to load dynamic content in to a div(myobj)... the code i have
>> so
>> far is more or less as follows. it creates a box with 2 links, that it
>> gets
>> from 'name_ctg'. the links, are category names and when clicked should
>> load
>> products.php, with the right product, as was determined by the link that
>> was
>> clicked. I hope that make sense... now the problem is that only the
>> first
>> link works, the second link does nothing. I hope someone can help.
>>
>> <script src="jquery.js"></script>
>>
>> <script>
>> $(document).ready(function(){
>> $("#generate2").click(function(){
>> $("#myobj").fadeOut("fast");
>> $("#myobj").slideToggle("slow");
>> $("#myobj").load("products.php?idctg_ctg=<?php echo
>> $row_categorys['idctg_ctg']; ?>");
>> });
>>
>> });
>> </script>
>>
>> <style type="text/css">
>> <!--
>> #myobj {
>> background-color: #9999CC;
>> height: 300px;
>> width: 500px;}
>>
>> -->
>> </style>
>> </head>
>>
>> <body>
>>
>> <div id="myobj" align="center">
>> <?php do { ?>
>> < a href="#" id="generate2" ><?php echo $row_categorys['name_ctg']; ?>
>> <br>
>> <?php } while ($row_categorys = mysql_fetch_assoc($categorys)); ?>
>> </div>
>> </body>
>> </html>
>> <?php
>> mysql_free_result($categorys);
>> ?>
>>
>> --
>> View this message in
>> context:http://www.nabble.com/can-someone-please-help-with-dynamic-links-prob...
>> Sent from the jQuery General Discussion mailing list archive at
>> Nabble.com.
>
>
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