I wonder why you would have a separate css class for each div. you
could do it using the solution given by JK or you could set the id of
each div tag that starts like 'jCalendar' and reference the elements
using the regular expression $('div[id^=jCalendar]')
sridhar.
On Dec 3, 9:00 pm, "Jeffrey Kretz" <[EMAIL PROTECTED]> wrote:
> I would recommend your elements having two classes. One which stays the
> same, and the second one which changes.
>
> e.g.
>
> <div class="jcalendar calendar0"></div>
> <div class="jcalendar calendar1"></div>
> <div class="jcalendar calendar2"></div>
> <div class="jcalendar calendar3"></div>
>
> Then you could grab it with
>
> $('div.jcalendar');
>
> JK
>
> -----Original Message-----
> From: [email protected] [mailto:[EMAIL PROTECTED] On
>
> Behalf Of light-blue
> Sent: Wednesday, December 03, 2008 5:40 PM
> To: jQuery (English)
> Subject: [jQuery] Targetting .class-0 .class-1 .class-2 .class-3
>
> This is a beginner question. Does anyone know how to target
>
> $('.jquery-calendar-0')
> $('.jquery-calendar-1')
> $('.jquery-calendar-2')
> $('.jquery-calendar-3')
> etc...
>
> I need to run the following, where X is the number, but I don't know
> how many X exist until after the page renders.
> $('.jquery-calendar-X').calendar( {stuff} )
>
> I can't find the solution in Learning Jquery (Chaffer and Swedberg),
> at least not in Chapter 2 How to Get Anything You Want. ;-)
>
> Thanks!
