Thanks anyway .. i found simpler solutions as referred by richo :)
$(document).ajaxError(function(event, request, setting)
{
var re = /<br\/>|<br>/g; // for replacing all <br/
> with empty string in error 404
var txt = request.responseText.replace(re,"");
jqalert(txt,"Server Error");
});
On Dec 15, 8:57 am, MareceK <[email protected]> wrote:
> Solution of your problem:
>
> error: function (xhr, ajaxOptions, thrownError) {
> if(xhr.status == 404) {
> // some error
> }
> else if(xhr.status == 403) {
> // another error
> }
> else {
> // default error
> }
>
> }
>
> On 24. Nov, 16:21 h., ricardobeat <[email protected]> wrote:
>
> > The XHR object and the error are passed as arguments to the ajaxError
> > callback:
>
> > $.ajaxError(function(event, XHRObject, options, errorThrown){
> > console.log( XHRObject.responseText, errorThrown );
>
> > });
>
> > seehttp://docs.jquery.com/Ajax/ajaxError#callback
>
> > On Nov 24, 4:09 am, Adwin Wijaya <[email protected]> wrote:
>
> > > how about using ajaxError events ? but I dont know how to capture the
> > > response text if 404 / 500 errors occured.
> > > can i use that instead of $.ajax ... ?
>
> > > thanks !
>
> > > On Nov 24, 12:18 pm, "Jeffrey Kretz" <[email protected]> wrote:
>
> > > > The best way would be to use the $.ajax call directly (both the post
> > > > and the
> > > > get function call $.ajax internally).
>
> > > > $.ajax({
> > > > type:'GET',
> > > > url:'somepath.php',
> > > > dataType:'json',
> > > > success:do_something,
> > > > error:do_something_else
>
> > > > });
>
> > > > function do_something(results) {
> > > > ///
>
> > > > }
>
> > > > function do_something_else() {
> > > > ///
>
> > > > }
>
> > > > JK
>
> > > > -----Original Message-----
> > > > From: [email protected] [mailto:[email protected]] On
>
> > > > Behalf Of Adwin Wijaya
> > > > Sent: Sunday, November 23, 2008 8:58 PM
> > > > To: jQuery (English)
> > > > Subject: [jQuery] how to capture error 500/404 ?
>
> > > > Hi,
>
> > > > how to capture error that produced by server (err 505 or 404) inside
> > > > $.post() and $.get() ?
>
> > > > thanks !!!