I hope you are using jQuery 1.2.6
Try these
$(myImage).width(width);
$(myImage).height(width/0.75);
On Dec 23, 11:43 pm, Paddy Joy <paddy...@gmail.com> wrote:
> Hope someone can help out here, I'm new to jquery and can't figure out
> what I have done wrong here.
>
> The following code works ok in FF and IE, it is a function that
> appends an image to a div and sets the width/height of that image.
>
> function showImage(src,divid,width)
> {
> var myImage = new Image();
> $(myImage).load(function()
> {
> $(divid).append(this)
> });
> $(myImage).attr("src", src);
> $(myImage).attr("width", width);
> $(myImage).attr("height", width/0.75);
>
> }
>
> I have modified the code so that the image fades in. This works fine
> in FF but in IE the image displays at its original dimensions and not
> at the dimensions I have set in the code.
>
> function showImage(src,divid,width)
> {
> var myImage = new Image();
> $(myImage).load(function()
> {
> $(this).hide();
> $(divid).append(this)
> $(this).fadeIn("fast");
> });
> $(myImage).attr("src", src);
> $(myImage).attr("width", width);
> $(myImage).attr("height", width/0.75);
>
> }
>
> Anyone any ideas?
>
> Paddy
