What happens with:
$(".tablesorter")
.tablesorter({widthFixed: true, widgets: ['zebra']})
.tablesorterPager({container: $("#pager")})
On Jan 12, 3:11 pm, "Varun Khatri" <khatri.vk1...@gmail.com> wrote:
> Here I have attached 3 files ... Its just a simple example
> I am trying this coz all my tables are dynamic (made at runtime)
> can you please check and let me know ...
> I have already spent hours for just 1 thing :
>
> Thanks
> I really appreciate the effort
> Varun
>
> On Mon, Jan 12, 2009 at 11:59 AM, MorningZ <morni...@gmail.com> wrote:
>
> > Without seeing a working (errr, "non working") page, constantly
> > posting the same piece of non-working code is not helping others help
> > you
>
> > How about just using a class?
>
> > On Jan 12, 2:51 pm, "Varun Khatri" <khatri.vk1...@gmail.com> wrote:
> > > well to me both returned same value.... So I agree
> > > But still cant find solution to problem:
>
> > > *alert($("#"+serverIdPrefix+"table1").size());// still returns 1*
>
> > > $("#"+serverIdPrefix+"table1")
> > > .tablesorter({widthFixed: true, widgets: ['zebra']})
> > > .tablesorterPager({container: $("#pager")})
>
> > > *//still doesnot work*
>
> > > Is there any other mistake that you can think of that I am making here ,
> > I
> > > know it should be pretty simple ....
> > > But I am unable to make it work
>
> > > Thanks
> > > Varun
>
> > > On Mon, Jan 12, 2009 at 11:48 AM, MorningZ <morni...@gmail.com> wrote:
>
> > > > "you shouldn't use .length on a jQuery object, since that always
> > > > returns 1 afaik"
>
> > > > size and length are equivalent, well, except that "size" is slower
>
> > > > Straight from the docs:
>
> > > > Length:
> > > > ----------------------------
> > > > The number of elements currently matched. The size function will
> > > > return the same value
>
> > > > Size:
> > > > ----------------------------
> > > > This returns the same number as the 'length' property of the jQuery
> > > > object. However, it is slightly slower, so length should be used
> > > > instead
>
> > > > On Jan 12, 2:25 pm, Lukas Pitschl | Dressy Vagabonds
> > > > <lu...@dressyvagabonds.com> wrote:
> > > > > you shouldn't use .length on a jQuery object, since that always
> > > > > returns 1 afaik.
> > > > > Use .size() instead. If your alert then still reports 1 you've
> > > > > selected the table
> > > > > correctly using jQuery, else you have to check your id.
>
> > > > > also your example implies, that the serverIdPrefix is not used. Check
> > > > > if html corresponds
> > > > > to your javascript on that.
>
> > > > > best regards,
>
> > > > > lukas pitschl
>
> > > > > Am 12.01.2009 um 20:21 schrieb Varun Khatri:
>
> > > > > > alert($("#"+serverIdPrefix+"table1").length));
> > > > > > This returns 1 ....
>
> > > > > > I dint get it
> > > > > > Plz help
> > > > > > Thanks
> > > > > > Varun
>
> > > > > > On Mon, Jan 12, 2009 at 4:26 AM, MorningZ <morni...@gmail.com>
> > wrote:
>
> > > > > > in the "runat=server" version, put
>
> > > > > > alert($("#"+serverIdPrefix+"table1").length));
>
> > > > > > right before the tablesorter line.... believe me, as a .NET
> > > > > > programmer myself, the runat=server is *not* causing tablesorter
> > (or
> > > > > > jQuery) to break, you definitely are not jQuery-selecting the table
> > > > > > properly
>
> > > > > > On Jan 12, 6:14 am, Genus Project <genusproj...@gmail.com> wrote:
> > > > > > > when the table is generated by server side code, are you sure you
> > > > > > are
> > > > > > > calling the correct selector ("#"+serverIdPrefix+"table1) ? maybe
> > > > > > you
> > > > > > > missed some letter or something. you can use firebug to examine
> > the
> > > > > > > generated table html to see if you are in fact calling the
> > correct
> > > > > > > selector. If you are, it really doesnt matter if the table is
> > runat
> > > > > > > server or not. They all transform to HTML fragments.
>
> > > > > > > On Jan 12, 7:52 am, varun <khatri.vk1...@gmail.com> wrote:
>
> > > > > > > > Hi
> > > > > > > > I was trying to use jquery table sorter plugins:
>
> > > > > > > > when ever I use it like :
> > > > > > > > <table id="table1" cellspacing="1" class="tablesorter" >
> > > > > > > > //row and column here
> > > > > > > > </table>
>
> > > > > > > > and jquery:
> > > > > > > > $("#table1")
> > > > > > > > .tablesorter({widthFixed: true, widgets: ['zebra']})
> > > > > > > > .tablesorterPager({container: $("#pager")})
>
> > > > > > > > It works fine..
>
> > > > > > > > how ever if i use :
> > > > > > > > <table id="table1" cellspacing="1" class="tablesorter"
> > > > > > > > runat="server">
> > > > > > > > //row and column here
> > > > > > > > </table>
>
> > > > > > > > and jquery:
> > > > > > > > $("#"+serverIdPrefix+"table1")// serverIdPrefix nicely found
> > > > > > what is
> > > > > > > > attached by server to id of table
> > > > > > > > .tablesorter({widthFixed: true, widgets: ['zebra']})
> > > > > > > > .tablesorterPager({container: $("#pager")})
>
> > > > > > > > it doesnt work when ever table is runat="server"
>
> > > > > > > > can some one help?
>
> > > > > > > > Thanks
> > > > > > > > Varun
>
>
>
> Default3.aspx
> 145KViewDownload
>
> jquery.tablesorter.js
> 31KViewDownload
>
> sort.js
> < 1KViewDownload
