It works by referencing the method with bracket or array notation. You can
reference properties and methods of an object this way. For example:
var obj = { test1: 'test_one', test2: 'test_two' };
alert( obj['test1'] ) // alerts test_one
alert( obj.test1 ) // also alerts test_one
The other code doesn't work because your aren't looking for a property on an
object. To make it work you evaluate the expression and then call the method
like this.
(expr ? 'a' : 'a')();
However, since your function 'a' is global it is a method of the window. You
could use bracket notation to reference the method like this.
window[ (expr ? 'a' : 'a') ]()
--
Brandon Aaron
On Sun, Jan 18, 2009 at 9:48 PM, Ami <aminad...@gmail.com> wrote:
>
> Thank you.
> It's working :)
>
> Can you put a function name in an array ?!
>
> May you explain me WHY it's working?
> $('div')[ (true? 'next' : 'before') ]().hide()
>
> I tried also this:
> function a() {alert('Function a')}
> [expr ? 'a' : 'a']()
> but it's didn't work. why?
>
> On Jan 19, 5:15 am, Brandon Aaron <brandon.aa...@gmail.com> wrote:
> > I believe you are looking for the following syntax:
> > $(selector)[ (expr ? 'next' : 'before') ]().show();
> >
> > --
> > Brandon Aaron
> >
> > On Sun, Jan 18, 2009 at 9:12 PM, Ami <aminad...@gmail.com> wrote:
> >
> > > Sorry about my grammar, English isn't my lang.
> >
> > > I am trying to write code like that:
> > > var expr=true,selector='div';
> > > $(selector) (expr ? .next() : .before() ). show();
> >
> > > But it's not JS syntax. So how can I do it?
> >
> > > I know,that I can do it like that:
> > > if (expr) $(selector)..before(),show() else
> > > $(selector).next().show()
> >
> > > But I am trying to find a solution, that return a jQuery object.
> >
> > > Thank you.
>
