And I'd recommend json_encode() in PHP and specifying 'json' as the datatype on the ajax call. Otherwise you may find the datae is not quite what you expect (likehaving a trailing space or \n, and so on.
On Mar 8, 5:45 pm, James <[email protected]> wrote: > In your PHP script, you're suppose to print (echo) your response. Make > sure to put an 'exit' afterwards so you don't continue processing the > rest of your script and return (print) unexpected content. > > On Mar 8, 11:17 am, Ethan <[email protected]> wrote: > > > Hi out there. I'm having a little trouble with my .ajax. Here's the > > function: > > > var name = $('#username').val(); > > var pass = $('#pass').val(); > > > $.ajax({ > > url: 'signin.php', > > type: 'GET', > > data: 'username=' + name + '&pass=' + pass, > > success: function(submitreturn){ > > alert(submitreturn); > > } > > }); > > > Here's signin.php: > > > <?php > > > require_once("classes/Login.php"); > > > $user = $_GET['username']; > > $pass = $_GET['pass']; > > > $login = new Login(); > > > if($login->login_user($user, md5(md5($pass) . POSTPASSKEY))) > > { > > return "I DID IT";} > > > else > > { > > return "I DIDNT DO IT"; > > > } > > > ?> > > > Okay, so here's my question. When the .ajax runs, the alert window > > contains the string that was in the username input, and <br />. Why > > is this? Why isn't submitreturn the value that was returned by > > signin.php? How can I get the value returned by signin.php? > > > Thanks for your help! > > > -Ethan
