So basically you just want to know how many <span> tags there are?
If so, something like this could work (untested):

var count = $("div.visual-cue span").length;

On Aug 24, 10:31 am, bombaru <bomb...@gmail.com> wrote:
> I'm trying to add a navigational aid to a carousel that I'm working
> on. Basically, I want to visually display the number of results in the
> carousel and then highlight the result that is currently in the first
> position as the user scrolls through the result set - providing a
> visual cue to the user as to where they are in the result set. I've
> seen this before on other carousels and it's sort of the same concept
> that Apple uses in the iPhone and iPod screens. I know this can be
> done rather easily with a bit of jQuery, but my brain is fried. You
> can see a mock-up of what I'm trying to achieve here:
>
> http://rule13.com/development/carousel.gif
>
> I'm trying to loop through the result set and count how many items are
> returned... then display something like the image above.  As a user
> navigates through the carousel, an active state is added to the visual
> cue.  The code I am working with for the visual cue section is
> currently just a bunch of span tags (I'm open to alternate
> approaches).  The number of <span> tags returned would be the same
> number of results returned in the carousel.
>
> <div class="visual-cue">
>         <p><span></span><span></span><span class="active"></
> span><span></span><span></span><span></span><span></span><span></
> span><span></span><span></span></p>
>       </div>
>
> Here's the CSS:
>
> /* visual cue */
> #accessorize div.visual-cue {height:16px; line-height:16px;
> position:absolute; right:0; width:266px; top:-40px;}
> #accessorize div.visual-cue p {text-align:right; line-height:16px;
> float:right;}
> #accessorize div.visual-cue p span {display:block; background:#fff;
> width:10px; height:10px; border:2px solid #EFEFEF; margin-left:2px;
> float:left;}
> #accessorize div.visual-cue p span.active {background:#D3D3D3; border:
> 2px solid #D3D3D3;}
>
> Does anyone know how I can achieve this or can someone steer me in the
> right direction?
>
> Thanks.

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