Instead of doing $(this).ajaxSubmit(options);
try
$('#formId').ajaxSubmit(options);
where #formId is the id of the form you are submitting.
On Feb 14, 8:58 am, NHARRY <nha...@live.co.uk> wrote:
> I have a form that is loaded using .load it is then posted using the
> jquery form plugin. But it won't post see code:
>
> <script type="text/javascript">
> $(document).ready(function() {
> //shows loading screen whilst posting via ajax
> $().ajaxStart($.blockUI).ajaxStop($.unblockUI);
>
> //post form add_customer ajax
> var options = {
> target: '#alert',
> };
> $('#add_customer').submit(function() {
> $(this).ajaxSubmit(options);
> return false;
> });
>
> //load form
> $('#theform').hide().load('form.php', function() {
> $(this).fadeIn();
> return false;
>
> });
> });
>
> </script>
>
> I am sure there are others that have had this problem. Help ismuch
> appreciated.
