Hi,
what about this:
$('.draggable').draggable({
helper: 'clone'
});
$('#droppable').droppable({
accept: '.draggable',
drop: function(ev, ui) {
$(this).append(ui.draggable.clone());
}
});
--
Bohdan
On Feb 3, 3:51 pm, dirk w <[email protected]> wrote:
> hello ui community!
> i would like to drop a draggable object and than append() it to an
> other list.
>
> but i dislike that the draggable object than get's removed from it's
> original place (i mean the place where it was before dropping it)
>
> is it possible to create a copy of the draggable object and than
> appending this one to the second place? so the real draggable object
> would still stay at it's original place.
>
> your help is much appreciated
> dirk
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