Even though I see you have jQuery UI included, your question does not seem to relate to jQuery UI ($.get is part of jQuery) so it would be better suited to the main jQuery list:
http://groups.google.com/group/jquery-en Thanks. - Richard On Mon, Mar 9, 2009 at 12:18 AM, wangsuya <[email protected]> wrote: > > Dear Everyone > > I make follow jQuery program using $.get but the return always is > undefined. Who can tell me why and How can I realize what I want? > Thanks in advance. > > Wang Suya > ............. > <html> > <head> > <script type="text/javascript" src="jquery-1[1].3.1.min.js"></script> > <script type="text/javascript" src="jquery-ui- > personalized-1.6rc6.js"></script> > <script> > function d(b){ > alert(b); > if(b == 5){ > $("input[name=bango]").attr("disabled","disabled"); > } > } > </script> > </head> > <body> > <table> > <tr><td><input type = "submit" name = "bango" id = "bango" value = "番号取 > 得"></td></tr> > </table> > <script type="JavaScript" src="jquery-1[1].3.1.min.js"></script> > <script> > $.get("get_su.php",function(data){ > alert(data.ban); > d(data.ban); > },"json"); > </script> > </body> > .... > get_su.php as bellow: > ........ > $json = new HTML_AJAX_JSON(); > $js = $json->encode(array("ban"=>"1111")); > print"$js"; > ........ > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "jQuery UI" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/jquery-ui?hl=en -~----------~----~----~----~------~----~------~--~---
