hi,

thanks dave.

as i mentioned that we are using this caching system for tabs. and we
have same ids present in each tab.so if i just hide then widgets in
those tabs will stop working. as multiple elements with same id will
be present in dom.

let me know what can i do to solve this in jquery or jquery-ui

regards,
saurabh

On Mar 22, 12:56 am, Fontzter <[email protected]> wrote:
> The quick guess is that you have a conflict with IDs.  By cloning, you
> now have two elements with the same ID, which is always a nightmare.
> Why not just create a hidden div and "hide" the stuff in there?  You
> can just use the move function to do so.  Depending on you needs you
> could just hide the element.
>
> $("#div2cache").after("<div class='plchldr'>Place Holder </div>").hide
> ();
>
> and bring it back like this:
>
> $("#div2cache").show().next().remove();
>
> Dave
>
> On Mar 21, 1:22 am, Saurabh <[email protected]> wrote:
>
> > hi,
>
> > in our application we are caching the dom when we change tabs. by
> > caching i mean we clone whole dom in a javascript variable and keep in
> > memory. once the user returns to the cached tab we render that dom
> > again.
>
> > what i have created here is a simple example of what we are doing in
> > our application. here in example i an taking full dom in a variable
> > when you press "cache and render again". you will see some alerts
> > which will explain the process.
>
> >http://reach1to1.com/sandbox/jquery/cache_problem/index.html
>
> > problem is datepicker or any other widget stops working once i do
> > this.
>
> > waiting for replies,
>
> > thanks in advance,
>
> > regards,
> > saurabh
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