hi, Please visist http://jsbin.com/aqaka/edit , then the problem will appear. The key point is that the 2 DIVs set to be droppable are overlapping,then the event of Dropping is triggered twice.
On Oct 12, 3:59 pm, "huangyingjie1...@126.com" <huangyingjie1...@126.com> wrote: > hi, > There are a couple of "DIV" ,one is on the top and the other is > below it. Let's call the top one TOP,and the below one BELOW. > Now the TOP contains many sub-DIV set to "float:right" that make > the TOP "overflow",so some sub-DIV are hidden into the back of BELOW. > Both sub-DIV and BELOW are set droppable for the pictures in > them,and both of them have set action fordropevent, for example > "alert('hello')"; of course, the pictures are draggable. > Now the problem comes while dragging picture from sub-DIV in TOP > to BELOW. If the area where the pictrue drops is just where the sub- > DIV hides,thedropevent is triggered twice,that is 'hello' alert > twice. And the picture factly drops into the sub-DIV ,not BELOW that I > expected. > I want the picture drops into the BELOW ,but it drops into the sub- > DIV;I want the event set in BELOW is triggered,but both event of > BELOW and sub-DIV are triggered. How to resolve the problem,thanks. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "jQuery UI" group. To post to this group, send email to jquery-ui@googlegroups.com To unsubscribe from this group, send email to jquery-ui+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/jquery-ui?hl=en -~----------~----~----~----~------~----~------~--~---