If you want offsets use .offset() not .position().
On Nov 30, 8:23 am, Charles H <charles.har...@gmail.com> wrote:
> In our framework, there may be multiple jqueryUI dialogs resulting
> from one ajax transaction. I would like to be able to ensure that
> dialogs do not overlap each other exactly by offsetting the x and y of
> each additional dialog by 10 pixels. The trouble is, I can't seem to
> get a real viewport y and y from the already existing dialogs. I've
> tried getting .position(), which only gives me 'center', also tried
> position().left, which seems to give me the left from some relative
> div, not the viewport. Nothing that I have tried seems to give me the
> correct viewport top and left of the previous dialog. Here is some
> pseudocode:
>
> // The current dialog, which has already been instantiated as
> centered but not yet shown.
> var currentWindow = etc...
>
> // If there is already a dialog open, shift currentWindow by 10
> pixels Y and X
> if (this.fastJqueryUiWindows.length>0) {
>
> // Get the previously opened window
> var previousWindow = this.fastJqueryUiWindows
> [this.fastJqueryUiWindows.length - 1];
> if (! previousWindow){
> return;
> }
>
> // Here is where I need the x and y from the viewport, so that
> repositioning will be correct.
> var x = previousWindow.position().left + 10;
> var y = previousWindow.position().top + 10;
>
> // Set the x and y of the new dialog to be 10 px offset frmo
> underlying window.
> currentWindow .dialog('option', 'position', [x, y]);
>
> }
>
> The dialog always ends up at far screen left because position().left
> and top seem to reflect something other than the x and y on the
> viewport...
>
> Any suggestions would be greatly appreciated!
>
> Thanks,
> Charles Harvey
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