Thanks for the great answers and explanation. I tried them and it all
works!


On Dec 15, 7:58 am, Scott González <scott.gonza...@gmail.com> wrote:
> On Dec 14, 11:53 pm, David_ca <david.calling...@gmail.com> wrote:
>
> > For me it is more natural to do the same thing using the below syntax
> > but it does not work. Can someone tell me why it doesn't work and/or
> > show
> > my the best practice approach to create a variable of a widget object
> > instantiation and reference it
> > later.
>
> > $().ready(function() {
> >         var aGreen = $('#test4 .target').green4();
> >         aGreen.darker();
>
> > });
>
> $('#test4 .target').green4() returns a jQuery object. From that
> object, you can get to the actual plugin instance using the .data()
> method:
>
> var aGreen = $('#test4 .target').green4().data('green4);
> aGreen.darker();
>
> All plugin instances are stored using .data() with the name of the
> plugin as the key.
>
> > ///////////////////////////////////////////////////////////////////
> > Question 2) How make a function return something.
> > Supposing my widget has a getHello() method that returns a "hello"
> > string. How do I call that method of my widget. I tried the below code
> > but it
> > does not work.
> > $().ready(function() {
> >         var aGreen = $('#test4 .target').green4();
> >         console.log("response: "+ $('#test4 .target').green4
> > ('getHello'));
>
> > });
>
> This works as of 1.8a1. Returning any value besides the plugin
> instance or undefined, will now act as a getter. Returning the plugin
> instance or undefined (or no return value) will make the plugin call
> chainable. With 1.7.x, you can make a method that is a getter by
> doing:
>
> $.ui.green4.getter = 'getHello';
>
> The getter property is a space delimited list of methods that will act
> as getters. Note that this does not allow a single method to both be a
> getter and setter because it will never return the original jQuery
> object.
>
> > ///////////////////////////////////////////////////////////////////
> > Question 3) How to pass a parameter to a function.
> > Supposing I have setDarker(value) function that takes a parameter
> > How do I invoke that function. Below is the syntax I hope would
> > work but it doesn't.
>
> > $().ready(function() {
> >         var aGreen = $('#test4 .target').green4();
> >         aGreen.setDarker("big");
>
> > });
>
> Two options:
> 1) jQuery method: Use the jQuery object and pass the parameters as
> additional parameters to the plugin method.
>
> aGreen.green4('setDarker', 'big');
>
> 2) plugin instance: Get the plugin instance as shown above from
> question #1 and use the standard function syntax.
>
> aGreenInstance.setDarker('big');

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