Thanks,

I will try that now.

Appreciated.

-West415


Balázs Suhajda wrote:
> 
> The dialog takes your original markup and turns it into a dialog. When
> you change the dialog markup with ajax content, you're actually
> overwriting the original markup. To avoid this, you could place a <div
> class="feedback"> or something similar inside your dialog markup to
> contain you ajax feedback, and hide/show the form / feedback depending
> on the status of the process.
> 
> ...Just an idea :)
> 
> On Mon, Feb 8, 2010 at 11:00 AM, West415 <malik.robin...@gmail.com> wrote:
>>
>> Hi,
>>
>> I am using a a jquery dialog box and it works fine for the most part
>> except
>> I'm running into one problem.  So here is the flow.
>>
>> 1. User clicks a hyperlink and dialog is opened with a form
>> 2. User submits the form in the dialog via ajax and in theajax callback
>> the
>> contents of the form are replaced with a thank you/confirmation message.
>> 3. User clicks close on the dialog box
>>
>> Now, next time I click that link, it displays the thank you/confirmation
>> box
>> and not the form.   Whenever the link is clicked it should always display
>> the form, but it's like it's caching it and not calling function that
>> loads
>> the form.
>>
>> Any idea?
>>
>> West415
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> 
> 
> 
> -- 
> Best regards,
> Balázs Suhajda
> 
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