Title: Help need to understand message from JRUN

Hi,

I finally configured Windows 2000, SQL 7.0, Apache and JRUN and Servlets.

It seems to be hooked up properly. 

However, it came back with the following message as.

404 Not Found
/servlets/KeyDistribute:

allaire.jrun.JRunServletException: not found
        at allaire.jrun.file.FileServlet.service(FileServlet.java, Compiled Code)
        at allaire.jrun.servlet.JRunServletPool.service(JRunServletPool.java:83)
        at allaire.jrun.servlet.JRunSE.service(JRunSE.java:1013)
        at allaire.jrun.servlet.JRunSE.runServlet(JRunSE.java, Compiled Code)
        at allaire.jrun.servlet.JRunRequestDispatcher.forward(JRunRequestDispatcher.java:88)
        at allaire.jrun.servlet.JRunSE.service(JRunSE.java:1131)
        at allaire.jrun.servlet.JvmContext.dispatch(JvmContext.java:330)
        at allaire.jrun.jrpp.ProxyEndpoint.run(ProxyEndpoint.java:354)
        at allaire.jrun.ThreadPool.run(ThreadPool.java, Compiled Code)
        at allaire.jrun.WorkerThread.run(WorkerThread.java, Compiled Code)

Could someone tell me whether I am missing JRUNServletException.class under
Defaul-App\Web-Info\Classes or something else?

If I do need have the exception class, Could someone can share JAVA source code
which seems display the message somewhat easy to read?

JRUN is installed under C:\JRUN root directory.

Thank you in advance.
Hitae Lee.


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