On Fri, 31 Dec 2010 14:46:37 +0100, Dmitry A. Soshnikov
<[email protected]> wrote:
So, why does this code produces a SyntaxError:
function () {
...
}()
...
Try to provide as much complete explanation as possible. Also try to
answer without cheating ;)
Because an ExpressionStatement may not start with the token "function",
and a
FunctionDeclaration may not omit the function name identifier, so there is
no
matching rule in the syntax.
With the variable name, the first part does match a FunctionDeclaration,
but
there is no rule that allows an opening parenthesis after a function
declaration.
Or more indirectly: The syntax generally requires only one token of
look-ahead to
identify the production to use. It disallows an ExpressionStatment from
starting
with "function" (or "{") to avoid ambiguity with FunctionDeclaration (or a
statement
block). That means that the above cannot possibly be detected as an
immediate function
call, but only as a FunctionDeclaration with garbage at the end.
/L
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