John Resig's blog has a good example use-case of this.
What’s the optimal way, in JavaScript, to convert a query string like
“foo=1&foo=2&foo=3&blah=a&blah=b” into one that looks like this:
“foo=1,2,3&blah=a,b”?

http://ejohn.org/blog/search-and-dont-replace/



On Oct 23, 5:15 am, pete otaqui <[email protected]> wrote:
> Yes - I can see from both yours and Peter van der Zee's replies that "exec in 
> a loop" is a much better way of going.
>
> Thanks!
>
> Pete
>
> On 23 Oct 2011, at 12:52, Lasse Reichstein wrote:
>
>
>
>
>
>
>
> > On Sun, Oct 23, 2011 at 1:40 PM, pete otaqui <[email protected]> wrote:
>
> >> I wasn't really asking a question so much as noting down a useful 
> >> observation I'd made.
>
> >> As you can see from my examples, it's not just the matches from the global 
> >> RegExp that I'm after, it's also the sub patterns.  These are never 
> >> returned by anything when using a global RegExp.
>
> > They are returned by RegExp.prototype.exec, and they are available if
> > you use String.prototype.replace or String.prototype.split.
> > If you need to access them, you can just to use .exec in a loop.
>
> > String methods like String.prototype.match are not the most basic
> > operation on a RegExp, and it does indeed not return the captures when
> > used with a global regexp.
>
> > Personally, I rarely, if ever, use String.prototype.match for anything.
>
> >> My message was just about a technique which actually uses .replace with a 
> >> callback rather than .match as a way of getting everything about each 
> >> capture (including lastIndex, and all the sub patterns).
>
> > That's another way to do it, but it's rather wasteful, since you build
> > the result of .replace without actually needing it.
> > /L
>
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>
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>
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