I am facing the same problem, I am using lotus ' xml transformer to convert
my XML files into HTML for non XML capable browsers. I need to access the
XML generated by the JSP file before creating the XSLTInputSource.
I am using this code
ByteArrayOutputStream stream = new ByteArrayOutputStream();
XSLProcessor processor = new XSLProcessor();
XSLTInputSource xmlSource = new
XSLTInputSource("http://localhost:8080/applinet/xml/test.jsp");
XSLTInputSource xslStylesheet= new
XSLTInputSource("http://localhost:8080/applinet/xml/test.xsl");
XSLTResultTarget xmlOutput = new XSLTResultTarget(stream);
processor.process(xmlSource, xslStylesheet, xmlOutput);
out.print(stream.toString());
----- Original Message -----
From: Joe Milora <[EMAIL PROTECTED]>
Sent: Thursday, April 06, 2000 8:44 PM
Subject: Re: transforming the output stream
> Never mind, I was able to get it to work. I hope no one spent too
> much time thinking about it.
> But if anyone has a better idea for implementing this, I'm all
ears.
> thanks.
>
>
> > -----Original Message-----
> > From: Joe Milora
> > Sent: Thursday, April 06, 2000 8:02 AM
> > To: '[EMAIL PROTECTED]'
> > Subject: transforming the output stream
> >
> >
> >
> > Hi everyone.
> > I'm trying to design a jsp page similar to the following:
> >
> > static xml
> > <myTagLibrary:dynamicXML>...</..>
> >
> > <myTagLibrary:XSLStyle sheet="..." source=?this?>
> >
> > I'd like to get the previous output of the jsp(which will now be an XML
> > document) and transform
> > it into html using XSL. Is it possible to get access to the output
stream
> > and change it? Or do I need
> > a different approach? I've tried several variations so far without any
> > luck.
> >
> > thanks,
> > Joe Milora
>
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