Try java.net.URLDecoder.decode(String value) from JDK 1.2
> Hello Everybody,
> My problem is about the value passing through the
> querystring method.
> For Ex.
> click on the following links
> 1. Very Good
> 2. Very Bad
> 3. Very Nice
> Now what I want that when user click on any one of the above links then
> value should pass to the next page (Like 'Very Good' or 'Very Nice' or '
> Very Bad').
> On the next page I am using the getQueryString() method for getting the
> value. But the problem is that I get the value Like ' Very%20Good'.
> Is there any method or way by which I can get the original value
> without '%20' it means 'Very Good' . Please give some another solution
> except Java String manipulations (like substring() etc.).
> Query String doesn't have a fixed format. It may contain any number of
> spaces or '-' or any character.
> Thanks in Advance.
> With regards
> Pranav
>
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>
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===========================================================================
To unsubscribe: mailto [EMAIL PROTECTED] with body: "signoff JSP-INTEREST".
Some relevant FAQs on JSP/Servlets can be found at:
http://java.sun.com/products/jsp/faq.html
http://www.esperanto.org.nz/jsp/jspfaq.html
http://www.jguru.com/jguru/faq/faqpage.jsp?name=JSP
http://www.jguru.com/jguru/faq/faqpage.jsp?name=Servlets
