Yes Bhavadeep ..it's a better logic... Regards Raju ----- Original Message ----- From: "Bhavdeep Sharma" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Tuesday, July 29, 2003 5:55 PM Subject: Re: Top 3
> Hi, > > I think following logic is simpler than the Raju's > > int max1 = 0, max2 = 0, max3 = 0; > while (there are more no's in the database) > { > n = extract_next_number_from_db(); > if (n > max1) > { > if (n > max2) > { > if (n > max3) > { > max1 = max2; > max2 = max3; > max3 = n; > } > else > { > max1 = max2; > max2 = n; > } > } > else > { > max1 = n; > } > } > } > > result: max3 > max2 > max1 > > regards > > -----Original Message----- > From: Peter [mailto:[EMAIL PROTECTED] > Sent: Tuesday, July 29, 2003 5:39 PM > To: [EMAIL PROTECTED] > Subject: Re: Top 3 > > > thanks for all who shared the comments on my question > Dear Mr Raju BSN .. i was looking for exactly the same solution u suggested > thanks a lot > Best Regards > Peter > > ----- Original Message ----- > From: "Raju BSN" <[EMAIL PROTECTED]> > To: <[EMAIL PROTECTED]> > Sent: Tuesday, July 29, 2003 5:24 PM > Subject: Re: Top 3 > > > > Hi, > > > > Try the following sample logic if you are not able to get it done in the > SQL > > Query it self... > > > > int top1 = 0; > > int top2 = 0; > > int top3 = 0; > > > > int resultsetData = 0; > > > > > > While(resultset.next()) { > > > > resultsetData = resultset.getXXX("column_name"); > > > > if(resultsetData > top1) { > > if(top2 < top1) { > > if(top3 < top2) { > > top3 = top2; > > } > > top2 = top1; > > } > > top1 = resultsetData; > > } > > if(resultsetData < top1 && resultsetData > top2) { > > if(top3 < top2) { > > top3 = top2; > > } > > top2 = resultsetData; > > } > > if(resultsetData < top1 && resultsetData < top2 && resultsetData > top3 ) > { > > top3 = resultsetData; > > } > > > > } > > > > Hope this will help > > > > Regards > > Raju > > > > > > > > ----- Original Message ----- > > From: "Pradeep Kumar" <[EMAIL PROTECTED]> > > To: <[EMAIL PROTECTED]> > > Sent: Tuesday, July 29, 2003 4:33 PM > > > > > > > Use a query like this: > > > > > > select max(emp_id) from employee where emp_id <>(select max(emp_id) > from > > > employee) > > > > > > -----Original Message----- > > > From: Lakshmeenarayana [mailto:[EMAIL PROTECTED] > > > Sent: Tuesday, July 29, 2003 4:32 PM > > > To: [EMAIL PROTECTED] > > > Subject: > > > > > > put them in integer array and use Arrays.sort(int[] arr) method. > > > > > > > > > > > > -----Original Message----- > > > From: A mailing list about Java Server Pages specification and reference > > > [mailto:[EMAIL PROTECTED] Behalf Of Peter > > > Sent: Tuesday, July 29, 2003 3:48 PM > > > To: [EMAIL PROTECTED] > > > Subject: > > > > > > > > > hi i need a misc..hlp > > > this is no way related to this group but still i put this > question..since > > i > > > know this group has elite personalities with logical brain.. > > > assume there is a series of nos is 3,4,5,6,7,9 > > > the nos are from data base .. i want the maximum three nos in a three > > > variables .. > > > any java code will be helpful > > > no arrays please.. > > > > > > Best Regards > > > Peter > > > > > > ========================= > > > To unsubscribe: mailto [EMAIL PROTECTED] with body: "signoff > > > JSP-INTEREST". > > > For digest: mailto [EMAIL PROTECTED] with body: "set JSP-INTEREST > > > DIGEST". > > > > > > Some relevant archives, FAQs and Forums on JSPs can be found at: > > > > > > http://java.sun.com/products/jsp > > > http://archives.java.sun.com/jsp-interest.html > > > http://forums.java.sun.com > > > http://www.jspinsider.com > > > > > > > > > =========================================================================== > > > To unsubscribe: mailto [EMAIL PROTECTED] with body: "signoff > > > JSP-INTEREST". > > > For digest: mailto [EMAIL PROTECTED] with body: "set JSP-INTEREST > > > DIGEST". > > > > > > Some relevant archives, FAQs and Forums on JSPs can be found at: > > > > > > http://java.sun.com/products/jsp > > > http://archives.java.sun.com/jsp-interest.html > > > http://forums.java.sun.com > > > http://www.jspinsider.com > > > > > > > > > > > > DISCLAIMER: > > > This message (including attachment if any) is confidential and may be > > privileged. 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