Hi,
I have simple test data
//[[(x, y, (sin x -sin y)*10)| x <- [-6..6]] | y <- [-3..3]]
static String sinXminusSinY = "MULTIPOINT ("
  + "  (-6.0 -3.0 4.205355062587931 ),"
 + "(-5.0 -3.0 11.000442827230057 ),"
 + "(-4.0 -3.0 8.979225033677954 ),"
 + "(-3.0 -3.0 0.0 ),"
 + "(-2.0 -3.0 -7.681774187658145 ),"
 + "(-1.0 -3.0 -7.003509767480293 ),"
 + "(0.0 -3.0 1.4112000805986722 ),"
 + "(1.0 -3.0 9.825909928677637 ),"
 + "(2.0 -3.0 10.50417434885549 ),"
 + "(3.0 -3.0 2.8224001611973444 ),"
 + "(4.0 -3.0 -6.15682487248061 ),"
 + "(5.0 -3.0 -8.178042666032713 ),"
 + "(6.0 -3.0 -1.3829549013905864) ," etc

Next I triangulate this and get subdivision

QuadEdgeSubdivision subdiv = builder.getSubdivision();

Now I need to fill an array [-6, 6]x[-3, 3]

and I try to interpolate my data in cycle
double val = interpolateZ(subdiv, new Coordinate(myX, myY));

//(I found this on Stackoverflow)
public static double interpolateZ(QuadEdgeSubdivision quadEdgeSubdivision,
Coordinate coordinate) {
        QuadEdge edge = quadEdgeSubdivision.locate(coordinate);
        System.out.println(edge.toString());///!!!See below
        return new Vertex(coordinate.x,
coordinate.y).interpolateZValue(edge.orig(), edge.dest(),
edge.oNext().dest());
    }

But I have a NaN processing column of my sample data.
When I print edge I get strange result.  I have no any 126, 123 in my
programm.
LINESTRING ( -126.0 -123.0, -6.0 -3.0 )
LINESTRING ( -126.0 -123.0, -6.0 -2.0 )
LINESTRING ( -126.0 -123.0, -6.0 -1.0 )
LINESTRING ( -126.0 -123.0, -6.0 0.0 )
LINESTRING ( -126.0 -123.0, -6.0 1.0 )
LINESTRING ( -126.0 -123.0, -6.0 2.0 )
LINESTRING ( -126.0 -123.0, -6.0 3.0 )

Is it normal or I did something wrong?
Thank you
CK
------------------------------------------------------------------------------
This SF.net email is sponsored by Windows:

Build for Windows Store.

http://p.sf.net/sfu/windows-dev2dev
_______________________________________________
Jts-topo-suite-user mailing list
[email protected]
https://lists.sourceforge.net/lists/listinfo/jts-topo-suite-user

Reply via email to