At compile time,
foo+=bar
becomes
foo = new StringBuffer().append(foo).append(bar).toString();
Thus, the observed output:
> nullhellohellohello
(One of the dangers of syntactic sugar, IMHO.)
HTH,
Ken
> -----Original Message-----
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of Tony Spencer
> Sent: Friday, October 29, 2004 4:38 PM
> To: 'Research Triangle Java User's Group mailing list.'
> Subject: [Juglist] Why doesn't this throw an exception?
>
> How come the following doesn't throw a runtime exception on
> the first iteration?
>
> String temp = null;
> for (int i = 0; i < 3; i++) {
> temp += "hello";
> }
>
> It doesn't seem like you should be able to append anything to
> a NULL string.
> The following is printed:
>
> nullhellohellohello
>
>
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>
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