Since we’re throwing out ways to do this, here’s another one:
w = Array(UTF8String, 100_000)
for i in 1:100_000
w[i] = @sprintf "col%d" i
end
I’ve come to really love using the *printf macros for anything that even
vaguely resembles formatting.
— John
On Jan 1, 2014, at 6:27 AM, [email protected] wrote:
> Hi,
>
> First of all you initialize "w" as Float64 which you do not probably want.
>
> For creating vector of strings you colud write:
>
> w = ["col" * string(i) for i in 1:100000]
>
> or:
>
> w = Array(ASCIIString, 100000)
>
> for i = 1:100000
> w [i] = "col" * string(i)
> end
>
> Bogumil
>
> On Wednesday, January 1, 2014 11:07:06 AM UTC+1, paul analyst wrote:
> I need a vector of string of subtitles: col1, col2, col3, ..., col100000
> How to join "col" phrase with numbers of var(i) ( in the loop)
>
> w = zeros (100000);
>
> for i = 1:100000
> w [i] =???
> end
>
> Paul
