Julia does part of transformation automatically for you.
If you look at
julia> @which a.'*b
At_mul_B(a,b) at operators.jl:122
You can see that the call is automatically rewritten to At_mul_B(a,b)
without making a transposed copy.
I am not sure what you can do about the result being a 1 element
Array{Complex{Float64},1} instead of just a Complex{Float64}.
Ivar
kl. 13:02:39 UTC+1 torsdag 2. januar 2014 skrev Sheehan Olver følgende:
>
>
> I want to do
>
> a.'*b
>
> where a and b are Vector{Complex}, but this returns an Array, not a
> constant, and probably does unneccesary memory allocation for when
> constructing a.'
>
> If it was
>
> a'*b
>
> I can just replace it with dot(a,b). Is there an equivalent that doesn't
> conjugate the first argument?
>
