Big Thx, just simply algebra... ;)
Is very speed now , thx Andreas
Paul
W dniu 2014-01-09 21:38, Andreas Noack Jensen pisze:
sum(czerw_rot[j;:].*Z[i;:]) can be calculated faster with
dot(vec(czerw_rot[j;:]),vec(Z[i;:])) but I guess that you can just do
F = Z*czerw_rot'
2014/1/9 paul analyst <[email protected]
<mailto:[email protected]>>
Is it possible to calculate the sum of the products of vectors
faster? without the loop?
(k,l)=size(Z);
(m,n)=size(czerw_rot);
F=zeros(k,m);println("stworzyl pusta F");
tic();
for j=1:m, i=1:k;
F[i,j]=sum(czerw_rot[j;:].*Z[i;:]);
end;
Z is very big ..
Paul
--
Med venlig hilsen
Andreas Noack Jensen
