[julia-users] Re: I have this error with PyCall, I need some help

[Steven G. Johnson]

The basic issue is that you can't overload function application in Julia 
(https://github.com/JuliaLang/julia/issues/2403).  So, unless PyCall can 
detect that an object corresponds to a "Function-like" type, it doesn't 
automatically convert it to Function or make it callable.