Reinterpret works for any length stings. See that the return type is
Array{Int,1}.
Just be careful when using reinterpret because (I believe) you will get the
native byte order (Litle endian/Big endian), and you should be careful to
follow the specification of the algorithm/transport protocoll.
kl. 21:05:21 UTC+1 tirsdag 11. mars 2014 skrev Robert Feldt følgende:
>
> Seems useful and I did not know about it. Strings in my case can be longer
> than 64 bits though but this is a useful building block. Thanks!
>
> Den tisdagen den 11:e mars 2014 kl. 20:13:05 UTC+1 skrev Avik Sengupta:
>>
>> Does this work?
>>
>> julia> a="abcdefgh"
>> "abcdefgh"
>>
>> julia> reinterpret(Int64, a.data)
>> 1-element Array{Int64,1}:
>> 7523094288207667809
>>
>>
>>
>> On Tuesday, 11 March 2014 16:07:35 UTC+5:30, Robert Feldt wrote:
>>>
>>> Implementing simple RSA crypto in pure Julia (not for actual
>>> sec-sensitive use) but for low-sec applications. But I have troubles with
>>> encoding strings as integers and back. The PKCS#1 crypto standard says that
>>> strings should be seen as 8-bit (octet) strings. I tried creating a Uint8[]
>>> with the byte values and converting to ASCIIString but that fails when the
>>> values are more than 7 bits. However, I cannot just convert to UTF8String
>>> instead since those might not be valid either.
>>>
>>> Ideas for how to do this cleanly? Current code below... Thanks!
>>>
>>> # Convert a non-negative integer i into an octet string.
>>> function i2osp(x::Integer, len = nothing)
>>> if typeof(len) <: Integer && (x >= 256^len)
>>> throw("integer is too large")
>>> end
>>>
>>> if x < 0
>>> throw("integer is negative")
>>> end
>>>
>>> bytes = Uint8[]
>>> while x > 0
>>> b = uint8(x & 0xff)
>>> push!(bytes, b)
>>> x = x >>> 8
>>> end
>>> str = convert(ASCIIString, reverse(bytes)) # Fails if any byte value >
>>> 127
>>>
>>> if typeof(len) <: Integer && (length(str) < len)
>>> str = repeat("\0", len - str) * str
>>> end
>>>
>>> return str
>>> end
>>>
>>>
