Here’s one way:
A = {
(4000,0.97613,1.6e6),
(2000,0.97613,800000.0),
(8000,0.97613,3.2e6),
(1000,0.97613,400000.0)
}Float64[row[3] for row in A] — John On Mar 11, 2014, at 9:34 PM, Matthew Crews <[email protected]> wrote: > (4000,0.97613,1.6e6) > (2000,0.97613,800000.0) > (8000,0.97613,3.2e6) > (1000,0.97613,400000.0)
