That is not possible yet. Please copy and paste the commands and errors from the terminal. It makes it easier to figure out what is wrong.
2014-04-07 18:03 GMT+02:00 paul analyst <[email protected]>: > Friends , case back: > > R = convert (Matrix {BigFloat}, cor (A)) > Ok, I have an array. Now I have carefully calculated in advance > eigenvectors: > (m, v) = e and g (R). > ERROR: No methods. :/ > How to calculate these vectors with high precision? > Paul > > > > W dniu sobota, 4 stycznia 2014 10:15:34 UTC+1 użytkownik Ivar Nesje > napisał: > >> Why do you want a BigFloat matrix? >> >> I am not saying it is not usefull, but in the examples here, you do the >> calculation first and then the conversion. Also when dealing with BigFloat >> it is important that you do not initialize them with with Float64 values >> that are not exactly what you want them to be, because lots of base 10 >> fractions are not represetable as a base 2 fraction. >> >> julia> BigFloat(0.1) >> 1.000000000000000055511151231257827021181583404541015625e-01 with 256 >> bits of precision >> >> julia> BigFloat("0.1") >> 1.000000000000000000000000000000000000000000000000000000000000000000000000000002e-01 >> with 256 bits of precision >> >> The better option is to initialize with a string. >> >> >> kl. 10:04:54 UTC+1 lørdag 4. januar 2014 skrev Andreas Noack Jensen >> følgende: >>> >>> convert(Matrix{BigFloat},cor(A)) >>> >>> >>> 2014/1/4 paul analyst <[email protected]> >>> >>>> How to create a correlation matrix (each other) with precision Big >>>> Float >>>> >>>> r = BigFloat (cor (A)) >>>> >>>> does not work ... >>>> >>>> Paul >>>> >>> >>> >>> >>> -- >>> Med venlig hilsen >>> >>> Andreas Noack Jensen >>> >> -- Med venlig hilsen Andreas Noack Jensen
