Nothing simple-to-use is yet in Base (but see https://github.com/JuliaLang/julia/pull/6437), but there are several options (roughly in the order easier-but-slower to harder-but-faster): - The Iterators package - The Grid package's Counter type - The Cartesian package (if you're running 0.3, an improved version of Cartesian is in Base)
--Tim On Friday, April 25, 2014 11:15:07 AM cnbiz850 wrote: > for ff[1] in factors, ff[2] in factors, ff[3] in factors, ff[4] in factors, > ff[5] in factors, ff[6] in factors, ff[7] in factors, > ff[8] in factors, ff[9] in factors > > To simplify the above, I tried the following but it didn't work: > > for ff[1:9] in factors > > Is there a similar simple way to do?
